(4x^2)-(3x^2-5)=20

Solution for (4x^2)-(3x^2-5)=20 equation:

Simplifying
(4x2) + -1(3x2 + -5) = 20

Reorder the terms:
(4x2) + -1(-5 + 3x2) = 20
(4x2) + (-5 * -1 + 3x2 * -1) = 20
(4x2) + (5 + -3x2) = 20

Reorder the terms:
5 + (4x2) + -3x2 = 20

Combine like terms: (4x2) + -3x2 = 1x2
5 + 1x2 = 20

Solving
5 + 1x2 = 20

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-5' to each side of the equation.
5 + -5 + 1x2 = 20 + -5

Combine like terms: 5 + -5 = 0
0 + 1x2 = 20 + -5
1x2 = 20 + -5

Combine like terms: 20 + -5 = 15
1x2 = 15

Divide each side by '1'.
x2 = 15

Simplifying
x2 = 15

Take the square root of each side:
x = {-3.872983346, 3.872983346}